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Two particles of medium disturbed by the wave propagation are at $x_{1} = 0 a n d x_{2} = 1 c m .$ The respective displacement (in cm) of the particles can be given by $y_{1} = 2 \sin 3 π t$ and $y_{2} = 2 \sin (3 π t - \frac{π}{2})$ . Wave velocity can be

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Detailed Solution

$Δ ϕ = \frac{2 π}{λ} (Δ x) \frac{π}{2} = \frac{2 π}{λ} (1) \Rightarrow λ = 4 c m; v = f λ = 6 c m^{- 1}$

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