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Two particles of medium disturbed by the wave propagation are at $x_{1} = 0$ and $x_{2} = 1 c m$ . The respective displacements (in cm) of the particles can be given by the equations:
$y_{1} = 2 \sin 3 π t, y_{2} = 2 \sin (3 π t - π / 8)$ . The wave velocity is (in cm/s) (Answer the nearest integer)

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answer is 24.

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Detailed Solution

$ω = 3 π f = \frac{ω}{2 π} = 1.5 Δ x = 1.0 c m ϕ = \frac{2 π}{λ} Δ x \Rightarrow \frac{π}{8} = \frac{2 π}{λ} \times 1 λ = 16 c m v = f λ = 16 \times 1.5 = 24 c m / s$

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