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Two particles P and Q simultaneously start moving from point A with velocities $15 {ms}^{- 1}$ and $20 {ms}^{- 1}$ respectively. The two particles move with accelerations equal in magnitude but opposite in direction. When P overtakes Q at B, then its velocity is $30 {ms}^{- 1}$ . The velocity of Q at point B will be

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$20 {ms}^{- 1}$

$15 {ms}^{- 1}$

$5 {ms}^{- 1}$

$30 {ms}^{- 1}$

answer is B.

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Detailed Solution

For P, 30 =15 + at or at = $15 {ms}^{- 1}$
For Q,v = 20 - at or v = 20 - 15 = $5 {ms}^{- 1}$

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