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Two particles P and Q simultaneously start moving from point A with velocities 15m/s and 20m/s respectively. The two particles move with acceleration equal in magnitude but opposite in direction. When P overtakes Q at B its velocity is 20m/s. The velocity of Q at point B will be

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30 m/s

5m/s

10m/s

15m/s

answer is D.

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Detailed Solution

$u_{Q}$ = 20m/s, $u_{P}$ = 15m/s
since P overtakes Q, P must be moving with acceleration '+a' and Q must be moving with acceleration '-a'.
$v_{P}$ = $u_{P}$ + at ⇒20 = 15 + at ⇒ at = 5m/s
$v_{Q}$ = $u_{Q}$ - at ⇒ $v_{Q}$ = (20 - 5)m/s = 15m/s

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