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Two particles $A$ and $B$ of masses $m_{A}$ and $m_{B}$ respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are $v_{A}$ and $v_{B}$ respectively, and the trajectories are as shown in the figure. The

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$m_{A} v_{A} < m_{B} v_{B}$

$m_{A} v_{A} > m_{B} v_{B}$

$m_{A} < m_{B}$ and $v_{A} < v_{B}$

$m_{A} = m_{B}$ and $v_{A} = v_{B}$

answer is B.

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Detailed Solution

For equal charge of the particles, radius

$r α (m v)$ and so $m_{A} v_{A} > m_{B} v_{B}$

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