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Two particles $A a n d B$ start from rest and move for equal time on a straight line. Particle $A$ has an acceleration of $2 m / s ²$ for the first half of the total time and $4 m / s ²$ for the second half. The particle B has acceleration $4 m / s ²$ for the first half and $2 m / s ²$ for the second half. Which particle has covered larger distance?

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Both have covered the same distance

Data insufficient

answer is B.

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Detailed Solution

Area under $v - t$ graph gives displacement. We can see that area for $B$ is greater than area for $A$ . Hence, $B$ has covered larger distance.

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