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Two pendulum bobs of mass m and 2m are attached to treads of length L suspended from a rigid support. Both the bobs are taken to a height H from the lowest point and then released so they collide elastically at the lowest point in their motion. Velocity of bob of mass m just after impact is $\frac{5}{3} \sqrt{ngH}$ the value of $n$ is ____ .

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answer is 2.

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Detailed Solution

$m_{1} = m, m_{2} = 2 m; u_{1} = \sqrt{2 gH}; u_{2} = \sqrt{2 gH}$

(but opposite in direction)

Apply $V_{1}, V_{2}$ formulas, we get $V_{1} = \frac{5}{3} \sqrt{2 gH}$

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