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Two pistons having low thermal conductivity divide an adiabatic container in three equal parts as shown. An ideal gas is present in the three parts A,B & C having initial pressures as shown and same temperatures. Now the pistons are released. Then the final equilibrium length of part A after long time will be :

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L / 8

L / 4

L / 6

L /5

answer is B.

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Detailed Solution

$n = \frac{PV}{RT}$
Final pressure and temperature is same hence volume will be in ratio of number of moles.

So the volumes lengths will be L/4, L/2, L/4.

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