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Two plates are at potentials –10 V and +30 V. If the separation between the plates be 2 cm. The electric field between them is

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1000 V/m

3000 V/m

2000 V/m

500 V/m

answer is A.

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Detailed Solution

$E = \frac{V}{d} = \frac{30 - (- 10)}{(2 \times 10^{- 2})} = 2000 V / m .$

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