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Q.

Two point charge _{$q_{1} = 4 μ C a n d q_{2} = 9 μ C$} are placed 20cm apart. The electric field due to them will be zero on the line joining them at a distance of

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a

8cm from _{$q_{1}$}

b

8cm form _{$q_{2}$}

c

_{$\frac{80}{13} c m from q_{1}$}

d

_{$\frac{80}{13} c m from q_{2}$}

answer is A.

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Detailed Solution

_{$E_{p} = 0$}

_{$\Rightarrow \frac{4}{x^{2}} = \frac{9}{{(20 - x)}^{2}}$}

_{$\Rightarrow \frac{20 - x}{x} = \frac{3}{2}$}

_{$\Rightarrow 40 - 2 x = 3 x$}

_{$\Rightarrow x = 8 c m$}

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