Two point charges +2C and +6C repel each other with a force of 12 N. If a charge q is given to each of these charges then they attract with 4N. Then value q is

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– 4C

+ 2C

+ 4C

– 2C

answer is C.

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Detailed Solution

$\begin{array}{l} 12 \propto (2 \times 6) - - - (1) (Repulsive) \\ - 4 \propto (2 + q) (6 + q) - - - (2) (attractive) \\ - \frac{12}{4} = \frac{12}{12 + 8 q + q^{2}} = q^{2} + 8 q + 16 = 0 \\ (q + 4)^{2} = 0 \Rightarrow q = - 4 C \end{array}$

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