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Q.

Two-point charges +8q and -2q are located at x = 0 and x = L respectively. The location of point on the x-axis at which the net electric field due to these two point charges is zero _______ (from the origin)

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a

2 L

b

8 L

c

$\frac{L}{4}$

d

4 L

answer is C.

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Detailed Solution

Let P be a point an x-axis where the electric field becomes zero.
Let x be the distance of null point from (-2q)
Question Image
At P $B_{8 q} = B_{- 2 q}$
$K . \frac{8 q}{{(L + x)}^{2}} = K . \frac{2 q}{x^{2}} \Rightarrow {(\frac{L + x}{x})}^{2} = 4 \Rightarrow \frac{L + x}{x} = 2 \Rightarrow L + x = 2 x \Rightarrow x = L$

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