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Two point charges placed at a distance r in air experience a certain force. Then the distance at which they will experience the same force in a medium of dielectric constant K is

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r/K

$\frac{r}{\sqrt{K}}$

$r + \sqrt{K}$

answer is C.

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Detailed Solution

$\frac{q_{1} q_{2}}{r^{2}} = \frac{q_{1} q_{2}}{Kr'^{2}} or Kr'^{2} = r^{2} or r' = \frac{r}{\sqrt{K}}$

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