Two point charges Q and –3Q are placed at some distance apart. If the electric field at the location of Q is $\overrightarrow{\mathrm{E}},$ the field at the location of –3Q is

Given data: The two-point charges Q and -3Q are positioned apart from one another.

Concept used: Electric field and electric field lines 

Detailed solution:

The Electric field of the given system can be expressed as:

$E=\frac{k\left(3Q\right)}{r^2}$

 $E^{\text{'}}=\frac{E}{3}$

For direction at$E^{\text{'}},$ As Q is positive particle electric field will be along the direction of $\overrightarrow{\mathrm{E}},$

$\overrightarrow{E}=\frac{\overrightarrow{E}}{3}$