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Q.

Two-point charges repel each other with a force of 100N. One of the charges is increased by 10% and the other is reduced by 10%. The new force of repulsion at the same distance would be

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a

121N

b

99N

c

100N

d

90N

answer is C.

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Detailed Solution

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100=kq1q2/r2 and  F=k(1.1q1)(0.9q2)/r2

⇒F100=0.99⇒F=99N

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Two-point charges repel each other with a force of 100N. One of the charges is increased by 10% and the other is reduced by 10%. The new force of repulsion at the same distance would be