Two point charges 3×10−6C and 8×10−6C repel each other by a force of 6×10−3N. If each of them is given an additional charge -6×106C, the force between them will be

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Two point charges $3 \times 10^{- 6} C$ and $8 \times 10^{- 6} C$ repel each other by a force of $6 \times 10^{- 3} N$ . If each of them is given an additional charge $- 6 \times 10^{6} C$ , the force between them will be

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$1 .5 \times 10^{- 3} N (repulsive)$

$1 .5 \times 10^{- 3} N (attractive)$

$2 .4 \times 10^{- 9} N (attractive)$

$2 .4 \times 10^{- 3} N (attractive)$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$F \propto Q_{1} Q_{2} \Rightarrow \frac{F_{1}}{F_{2}} = \frac{Q_{1} Q_{2}}{Q_{1}' Q_{2}'}$

$= \frac{3 \times 10^{- 6} \times 8 \times 10^{- 6}}{(3 \times 10^{- 6} - 6 \times 10^{- 6}) (8 \times 10^{- 6} - 6 \times 10^{- 6})} = \frac{3 \times 8}{- 3 \times 2} = - \frac{4}{1}$