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Two point charges $+ 9 e$ and $+ e$ are at 16 cm away from each other. Where should another charge q be placed between them so that the system remains in equilibrium

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12 cm from $+ e$

24 cm from $+ e$

12 cm from $+ 9 e$

24 cm from $+ 9 e$

answer is B.

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Detailed Solution

Suppose q is placed at a distance x from +9e, then for equilibrium net force on it must be zero i.e. $| F_{1} | = |F_{2}|$

Which gives $x_{1} = \frac{x}{\sqrt{\frac{Q_{2}}{Q_{1}}} + 1} = \frac{16}{\sqrt{\frac{e}{9 e}} + 1} = 12 cm$

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