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Two point charges $Q_{1}$ and $Q_{2}$ are positioned at points 1 and $2 .$ The field intensity to the right of the charge $Q_{2}$ on the line that passes through the two charges varies according to a law that is represented schematically in the figure. The field intensity is assumed to be positive direction coincides with the positive direction on the $x$ -axis. The distance between the charge is $l$ .
Find the sign of each charge.

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$Q_{1}$ is positive and $Q_{2}$ is constant

$Q_{1}$ is positive and $Q_{2}$ is negative

None of above

$Q_{1}$ is negative and $Q_{2}$ is positive

answer is A.

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Detailed Solution

Over charge $Q_{2}$ , field intensity is infinite along negative $x$ -axis. Therefore, $Q_{2}$ is negative.

Beyond $x > (I + a)$ , field intensity is positive. Therefore, $Q_{1}$ is positive.

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