Two point charges +q1 and +q2 separated by distance ‘d’ exert a net force of on a point charge + q kept on the line joining the two charges at a distance d/4 from q1. On mutually interchanging the positions of the charges q1 and q2 the third charge + q kept at the same point experiences a net force F→2. If F→1=2F→2 then the ratio q1/q2 may be

F1=14πϵ016q1qd2−16q2q9d2F2=14π∈016q2qd2−16q1q9d2Setting F¯1=2F¯2 and solving we Get q1q2=1911

F1=14πϵ016q1qd2−16q2q9d2F2=14π∈016q2qd2−16q1q9d2Setting F¯1=2F¯2 and solving we Get q1q2=1911

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Two point charges $+ q_{1} and + q_{2}$ separated by distance ‘d’ exert a net force of on a point charge + q kept on the line joining the two charges at a distance d/4 from q₁. On mutually interchanging the positions of the charges $q_{1} and q_{2}$ the third charge + q kept at the same point experiences a net force ${\vec{F}}_{2} . If |{\vec{F}}_{1}| = 2 |{\vec{F}}_{2}|$ then the ratio $q_{1} / q_{2}$ may be

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$F_{1} = \frac{1}{4 π ϵ_{0}} [\frac{16 q_{1} q}{d^{2}} - \frac{16 q_{2} q}{9 d^{2}}]$

$F_{2} = \frac{1}{4 π \in_{0}} [\frac{16 q_{2} q}{d^{2}} - \frac{16 q_{1} q}{9 d^{2}}]$

Setting $|{\bar{F}}_{1}| = 2 |{\bar{F}}_{2}|$ and solving we Get $\frac{q_{1}}{q_{2}} = \frac{19}{11}$

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