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Two point size bodies of same mass are knotted to a horizontal string one at the end, and the other at the midpoint of it. The string is rotated in horizontal plane with the other end as centre. If $T$ is tension in the string between centre of circles and first body then the tension in the string between the two bodies is

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$2 T$

$3 T / 2$

$T / 2$

$2 T / 3$

answer is C.

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Detailed Solution

$T^{1} = m (2 l) ω^{2}; T - T^{1} = ml ω^{2}; T = 3 ml ω^{2}$

$\Rightarrow T^{1} = \frac{2 T}{3}$

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