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Two point sources distant 0.1 meter away viewed by a telescope. The objective is covered by a screen having a hole of 1 mm width. If the wavelength of the light used is 6550 Å, then the maximum distance at which the two sources are seen just resolved, will be nearly:

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125.0m

165 m

131m

164m

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{d}{D} = \frac{1 .22 λ}{a}; \frac{0 .1}{D} = \frac{1 .22 \times 6550 \times 10^{- 10}}{1 \times 10^{- 3}} \\ D = \frac{10^{- 4}}{122 \times 655 \times 10^{- 11}} = \frac{10^{7}}{122 \times 655} = 125 .1 m \end{array}$

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