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Two point sources $S_{1}$ and $S_{2}$ , which are out of phase, emit sound waves of wavelength $2.0$ m. The phase difference between the waves arriving at point $P$ if $x_{1} = 18$ m and $x_{2} = 19$ m

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$π$

$2 π$

$\frac{π}{2}$

answer is A, D.

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Detailed Solution

$∆ x = 19 - 18 = 1 m$

As $λ = 2$ ,

Therefore, $1 m = \frac{λ}{2}, o r ϕ = π r a d$

So $∆ ϕ = π - π = 0 o r ∆ ϕ = π + π = 2 π$ .

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