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Q.

Two points charges q₁ and q₂ (=q₁/2) are placed at points A(0, 1) and B (1, 0) as shown in the figure. The electric field vector at point P(1, 1)
makes an angle q with the x–axis, then the angle q is\

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a

$\tan^{- 1} (0)$

b

$\tan^{- 1} (1)$

c

$\tan^{- 1} (\frac{1}{4})$

d

$\tan^{- 1} (\frac{1}{2})$

answer is A.

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Detailed Solution

Due to electric field is $\frac{k q_{1}}{r^{2}}$ along X axis and due to $q_{2}$ $\frac{k q_{2}}{r^{2}}$ along y axis

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