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Two points P and Q are maintained at the potentials of 10V and -4V respectively. The work done in moving 100 electrons from P to Q is

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$- 19 \times 10^{- 17} J$

$9.60 \times 10^{- 17} J$

$12.24 \times 10^{- 16} J$

$2.24 \times 10^{- 16} J$

answer is D.

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Detailed Solution

$w = (V_{2} - V_{1}) q = (- 4 - 10) (- 100 e)$

$= 2.24 \times 10^{- 16} J$

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