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Two poles of height 6 m and 11 m stands on a plane ground, if the distance between their feet is 12 m. Find the distance between their tops.

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13 m

14 m

15 m

20 m

answer is A.

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Detailed Solution

Given: Two poles
1st pole

AB is 11 m

2nd pole

CD is 6 m

Distance between both poles is,

BD = 12 m

Then, create a line segment CE parallel to line BD
So,

AE = AB - CD

AE = 11 - 5

AE = 6 m

△ AEC

from Pythagoras theorem,

{(AC)}^{2} = {(AE)}^{2} + {(AE)}^{2}

\Rightarrow {(AC)}^{2} = {(12)}^{2} + {(5)}^{2}

\Rightarrow {(AC)}^{2} = 144 + 25

\Rightarrow {(AC)}^{2} = 169

\Rightarrow AC = 13 m

Thus, the distance between their tops =

13 m

.
Correct option is 1.

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