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Q.

Two positive charges seperated by a distance 1m each other with a force of 0.45 N. If the combined charge is $15 μ C$ , the charges are

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a

18 $μ$ c, 8 $μ$ c

b

5 $μ$ c,10 $μ$ c

c

20 $μ$ c, 6 $μ$ c

d

13 $μ$ c,13 $μ$ c

answer is B.

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Detailed Solution

$F = \frac{k q_{1} q_{2}}{r^{2}} 0.45 = \frac{9 \times 10^{9} \times q \times 10^{- 6} (15 - q) \times 10^{- 6}}{1^{2}} q^{2} - 15 q + 50 = 0 q^{2} - 5 q - 10 q + 50 = 0 q (q - 5) - 10 (q - 5) = 0 q - 5 = 0 o r q - 10 = 0 q = 5 μ C o r 10 μ C a n d (15 - q) = 15 - 5 = 10 μ C$

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Two positive charges seperated by a distance 1m each other with a force of 0.45 N. If the combined charge is 15 μC , the charges are