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Two positive charges seperated by a distance 1m repel each other with a force of 0.45 N. If the combined charge is 15µC , the charges are

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$20 μC, 6 μC$

$5 μC, 10 μC$

$18 μC, 8 μC$

$13 μC, 13 μC$

answer is B.

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Detailed Solution

$F = \frac{1}{4 {πε}_{0}} \frac{{(q_{1})}^{2} {(q_{2})}^{2}}{d^{2}}$
$0 .45 = 9 \times 10^{9} \times \frac{{(q_{1} q_{2})}^{2}}{1^{2}}$ ............(1)

$q_{1} + q_{2} = 15 μC$ ..........(2)
solving, we get, $5 μC, 10 μC$

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