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Q.

Two positively charged particles each of mass 1.7×10^–27 kg and carrying a charge of 1.6×10^–19C are placed r distance apart. If each one experience a repulsive force equal to its weight. Find the distance between them.

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a

117 m

b

11.7 cm

c

117 cm

d

1.17 m

answer is C.

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Detailed Solution

$\begin{array}{l} F = mg \\ 9 \times 10^{9} \times \frac{{(1 .6 \times 10^{- 19})}^{2}}{r^{2}} = 1 .7 \times 10^{- 27} \times 9 .8 \\ \Rightarrow r^{2} = \frac{{(1 .6 \times 10^{- 19})}^{2} \times 9 \times 10^{9}}{1 .7 \times 10^{- 27} \times 9 .8} \\ \Rightarrow r = 11 .7 \times 10^{- 2} m \\ \Rightarrow r = 11 .7 cm \end{array}$

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