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Two projectiles, one fired from the surface of the earth with speed 5 rn/s and the other fired from the surface of a planet with initial speed 3 m/s, trace identical trajectories. Neglecting friction effect, the value of acceleration due to gravity on the planet is:

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5.9 m/s²

8.5 m/s²

16.3 m/s²

3.5 m/s²

answer is B.

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Detailed Solution

For same trajectories, R is same so
$g \propto v^{2} \Rightarrow g' = {(\frac{3}{5})}^{2} (9 .8) = 3 .5 m / s^{2}$

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