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Two rectangular blocks of masses 20 kg, 30 kg, are connected by a string & kept on a friction less horizontal table. If a force of 1000N is applied on 30 kg block away from 20 kg block then the tension in the string is _______________

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$450 N$

$400 N$

$350 N$

$500 N$

answer is B.

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Detailed Solution

Equation of unction of block $m_{2}$ is

$\begin{array}{l} F - T = m_{2} a \\ 1000 - T = 30 (\frac{T}{20}) \\ 1000 - T = \frac{3}{2} T \\ 2000 - 2 T = 3 T \\ T = \frac{2000}{5} = 400 N \end{array}$

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