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Two rectangular pieces of plane glass are laid one upon the other on a table. A thin strip of paper is placed between them at one edge so that a very thin wedge of air is formed. The plates are illuminated at normal incidence by 540-nm light from a mercury vapour lamp. Interference fringes are formed with 15 fringes per centimetre. Find the angle of wedge in multiples of 1/10000 of a radian (refractive index of air is 1)

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answer is 4.05.

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Detailed Solution

$\begin{array}{l} 2 (t_{1} - t_{2}) = λ \\ d = \frac{1}{15} c m \\ \tan θ = \frac{t_{1} - t_{2}}{d} \end{array}$

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