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Two resistors of resistance $200 K Ω 1 M Ω$ respectively form a potential divider with outer junctions maintained at potentials of + 3 and -15 V. The potential at x is

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+1 V

-0.6 V

0 V

-12 V

answer is B.

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Detailed Solution

A cross the branch same current flows.

$\begin{array}{l} i_{1} = i_{2} \\ \frac{3 - x}{0 .2 \times 10^{6}} = \frac{x + 15}{10^{6}} \\ 3 - x = 0 .2 x + 3 \Rightarrow 0 = 1 .2 x \\ x = 0 \end{array}$

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