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Q.

Two resistors R and 2R are connected in series in an electric circuit. The thermal energy developed in R and 2R are in the ratio


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a

2:1

b

1:2

c

4:1

d

1:4 

answer is B.

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Detailed Solution

The thermal energy will be in the ratio of 1:2
The resistor of resistance R ohm and 2R ohm are given
Now, current in series combination is same through its components. Let the current I flow through R as well as through 2R.
We know.
Thermal energy across resistor in time t sec = I2Rt
Let H1 and H2 be thermal energy across R and 2R respectively
H1 = I2Rt     and    H2 = I2(2R)t
Now,             H1H2 = I2 RtI2 2Rt = 12     
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