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Q.

Two riffles fire the same number of bullets in a given interval of time. The second fires bullets of mass twice that fired by the first and with a velocity that is half that of the first. The ratio of their powers is

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a

1 : 4

b

2 : 1

c

1 : 2

d

4 : 1

answer is D.

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Detailed Solution

$\frac{P_{1}}{P_{2}} = (\frac{m_{1}}{m_{2}}) (\frac{{v_{1}}^{2}}{{v_{2}}^{2}})$

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