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Q.

Two rigid bodies A and B rotate with angular momenta LA and LB respectively. The moments of inertia of A and B about the axies of rotation are IA and IB respectively. If IA=IB/4 and LA=5LB,, Then the ratio of rotational kinetic energy KA of A to rotational kinetic energy KB of B is given by

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a

KAKB=254

b

KAKB=100

c

KAKB=14

d

KAKB=54

answer is D.

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Detailed Solution

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KA=LA22lA=25LB22(4)lB

KB=LB22lB Now, KAKB=25×4=100

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