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Two rigid containers of same volume, contain ideal gases having same number of moles at same temperature one of the container contains diatomic gas A and the other one contains polyatomic gas B. If $E_{T}, E_{r} and U$ represent energy absorbed by a gas due to translational motion and rotational motion of molecules respectively and U be the internal energy of a gas, Then

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${(E_{T})}_{A} > {(E_{T})}_{B}$

${(E_{r})}_{A} = {(E_{r})}_{B}$

${(E_{T})}_{A} = {(E_{T})}_{B}$

Both (1) and (3) are correct

answer is C.

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Detailed Solution

For A, number of degrees of freedom for rotational motion = 2 and that for gas B = 3.

For translation motion, number of degrees of freedom for each gas = 3.

$∴ {(E_{r})}_{A} = 2 (\frac{KT}{2}) (n . N_{a}) = nRT$

${(E_{r})}_{B} = 3 (\frac{KT}{2}) (n . N_{a}) = \frac{3}{2} nRT$ .

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