Two rods A and B of identical dimensions are at temperatures 30∘C. If A is heated upto 180∘C and B upto T∘C , their lengths became same. The ratio of α of A and B is 4 : 3 then the value of T is

Δℓ1=Δℓ2ℓ1α1t1=ℓ2α2t2⇒α1α2=t2t143=T−30180−30⇒T=230∘C

Two rods A and B of identical dimensions are at temperatures 30∘C. If A is heated upto 180∘C and B upto T∘C , their lengths became same. The ratio of α of A and B is 4 : 3 then the value of T is

Δℓ1=Δℓ2ℓ1α1t1=ℓ2α2t2⇒α1α2=t2t143=T−30180−30⇒T=230∘C

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Two rods A and B of identical dimensions are at temperatures $30^{\circ} C$ . If A is heated upto $180^{\circ} C$ and B upto $T^{\circ} C$ , their lengths became same. The ratio of $α$ of A and B is 4 : 3 then the value of T is

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$230^{\circ} C$

$200^{\circ} C$

$100^{\circ} C$

$150^{\circ} C$

answer is D.

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$Δ ℓ_{1} = Δ ℓ_{2}$

$ℓ_{1} α_{1} t_{1} = ℓ_{2} α_{2} t_{2} \Rightarrow \frac{α_{1}}{α_{2}} = \frac{t_{2}}{t_{1}}$

$\frac{4}{3} = \frac{T - 30}{180 - 30} \Rightarrow T = 230^{\circ} C$

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Two rods A and B of identical dimensions are at temperatures 30∘C. If A is heated upto 180∘C and B upto T∘C , their lengths became same. The ratio of α of A and B is 4 : 3 then the value of T is

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Two rods A and B of identical dimensions are at temperatures $30^{\circ} C$ . If A is heated upto $180^{\circ} C$ and B upto $T^{\circ} C$ , their lengths became same. The ratio of $α$ of A and B is 4 : 3 then the value of T is