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Two rods of equal length and area of cross-section are kept parallel and lagged between temperature 20°C and 80°C. The ratio of the effective thermal conductivity to that of the first rod is [the ratio (K₁/K₂) = 3 : 4]

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4 : 7

7 : 6

7 : 8

7 : 4

answer is B.

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Detailed Solution

For parallel combination of two rods of equal length and equal area of cross-section:
$K = \frac{K_{1} + K_{2}}{2} = \frac{K_{1} + \frac{4 K_{1}}{3}}{2} = \frac{7 K_{1}}{6}; Hence \frac{K}{K_{1}} = \frac{7}{6}$

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