Two rods of same length and material transfer a given amount of heat in 12 s, when they are joined end to end (i.e, in series). But when they are joined in parallel, they will transfer same heat under same conditions in a time ___seconds.

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answer is 3.

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Detailed Solution

$Δ t = \frac{Δ Q (Δ x)}{K A (Δ T)}$

When two rods of same length are joined in parallel, $A \to 2$ and $(Δ x) \to \frac{1}{2} t i m e s$

$∴ Δ t$ becomes $\frac{1}{4} t i m e s i . e ., \frac{1}{4} \times 12 s = 3 s$

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