Two rods one of copper and the other of steel each of radius 5 cm and of length 120 cm are joined in series. The ends of the rods are at 100∘C and 0∘C respectively as shown. The temperature at the the interface of copper-steel junction is nearly ( Thermal conductivity of copper is 460 Wm−1∘C−1 and that of steel is 46 Wm−1∘C−1)

(ΔQΔt)Cu=(ΔQΔt)stee1 460×A×(100−T)120 = 46×A×(T−0)120∴T=91∘C

Two rods one of copper and the other of steel each of radius 5 cm and of length 120 cm are joined in series. The ends of the rods are at 100∘C and 0∘C respectively as shown. The temperature at the the interface of copper-steel junction is nearly ( Thermal conductivity of copper is 460 Wm−1∘C−1 and that of steel is 46 Wm−1∘C−1)

(ΔQΔt)Cu=(ΔQΔt)stee1 460×A×(100−T)120 = 46×A×(T−0)120∴T=91∘C

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Two rods one of copper and the other of steel each of radius 5 cm and of length 120 cm are joined in series. The ends of the rods are at $100^{\circ} C$ and $0^{\circ} C$ respectively as shown. The temperature at the the interface of copper-steel junction is nearly ( Thermal conductivity of copper is $460 {Wm}^{- 1 \circ} C^{- 1}$ and that of steel is $46 {Wm}^{- 1}^{\circ} C^{- 1})$

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102ºC

82ºC

91ºC

78ºC

answer is B.

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Detailed Solution

${(\frac{ΔQ}{Δt})}_{Cu} = {(\frac{ΔQ}{Δt})}_{stee 1}$ $\frac{460 \times A \times (100 - T)}{120} = \frac{46 \times A \times (T - 0)}{120}$
$∴ T = 91^{\circ} C$

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