Two samples X and Y of a pure substance obtained by two different methods contain elements P and Q. Substance X has a mass of 2.25 g and contains 0.90 g of O. Substance Y is made up of 60% P and
40% O by weight. This is an illustration of

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Gay-Lussac’s law of combining volumes

Law of constant proportions

Law of reciprocal proportions

Law of multiple proportions

answer is B.

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Detailed Solution

Law of constant proportions

Mass of $X = 2.25 g$

Mass of $P = 2.25 - 0.90 = 1.35 g$

Ratio of masses of P and Q in sample

$X = 1.35 : 0.90 i . e . 1.5 : 1$

Ratio of masses of P and Q in sample

$Y = 60 : 40 i . e . 1.5 : 1$

As the ratio of the masses of P and Q in two samples X and Y is constant i.e. 1.5 : 1 so, this is on illustration of law constant proportions.

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