Two satellites of mass m and 9m are orbiting a planet in orbits of radius R. Their periods of revolution will be in the ratio of [KCET 2011] 

As we know,

From Kepler's law, time period of satellite is  $T^2=\frac{4{\pi }^2{R}^3}{GM}$

$T_{\text{sat }}=2\pi \sqrt{\frac{(R+h{)}^2}{G{M}_e}}$

As two satellites of masses m and 9m are orbiting a planet of radius R, their time periods will remain same, i.e. in the ratio 1 : 1, because time period of satellite does not depend on its mass.