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Q.

Two satellites of same mass of a planet in circular orbits have periods of revolution 32 days and 256 days- If the radius of the orbit of the first is R, then the :
(i) radius of the orbit of the second is 8R
(ii) radius of the orbit of the second is 4R
(iii) total mechanical energy of the second is greater than that of the first
(iv) kinetic energy of the second is less than that of the first

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a

(i, iii)

b

(ii, iv)

c

(ii, iii, iv)

d

(i, ii, iii)

answer is C.

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Detailed Solution

Use Kepler's second law T∝R3/2
KE=GMm2R,TE=−GMm2R

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