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Two satellites P, Q are revolving around earth in different circular orbits. The velocity of P is twice the velocity of Q. If the height of P from earth’s surface is 1600 km. The radius of orbit of Q is ( R =6400 km).

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20000km

40000km

1600km

32000km

answer is C.

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Detailed Solution

Given, v_P = 2v_Q
$\sqrt{\frac{GM}{r_{P}}} = 2 \sqrt{\frac{GM}{r_{Q}}} \to r_{Q} = 4 r_{P}$

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