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Two satellites $S_{1}$ and $S_{2}$ are revolving in circular orbits around a planet with radius $R_{1} = 7200 k m$ and $R_{2} = 800 k m$ respectively. The ratio of speed of satellite $S_{1}$ to the speed of satellite $S_{2}$ in their respective orbits would be $\frac{1}{x}$ where $x =$

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answer is 3.

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Detailed Solution

We know that orbital velocity is given as

$V = \sqrt{\frac{G M}{x}} ∴ V \propto \frac{1}{\sqrt{x}} \Rightarrow \frac{V_{1}}{V_{2}} = \sqrt{\frac{r_{2}}{r_{1}}} = \sqrt{\frac{800}{7200}} = \frac{1}{3}$

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