Two separate air bubbles of radii 0.002 m and 0.004 m formed of the same liquid (surface tension $0.07 N m^{- 1})$ come together to form a double bubble. The radius and the sense of curvature of internal film surface, common to both the bubbles is

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0.002 m concave towards smaller bubble

0.003 m concave towards smaller bubble

0.004 m concave towards smaller bubble

0.005 m concave towards smaller bubble

answer is C.

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Detailed Solution

$r = \frac{r_{1} r_{2}}{r_{1} ~ r_{2}} = \frac{0.002 \times 0.004}{0.002}$

$= 0.004 m$

Pressure in smaller bubble will be larger. So, the concave part will be towards smaller bubble.

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