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Q.

Two ships are approaching a light house from opposite directions. The angles of depression of two ships from top of the light house are 30°and 45°. If the distance between two ships is 100m, the height of the light house is ____.


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Detailed Solution

Let h be the height of the light house, x be the distance of the ship making angle of 45from the base of the light house.
It is given that the distance between two ships is 100m. Therefore the distance between the ship making an angle of 30°with the light house to the base of the light house will be 100− x
Question ImageIn ΔACD, we will use the trigonometric function to get the relation between x and h. Therefore we get
tan 45° =perpendicularbase=hx
We know that tantan 45° is equal to 1. Therefore, we get
⇒1=hx
⇒h= x……………….(1)
We will now take the triangle ABC and use the trigonometric function to find the relationship between x and h.
Therefore, we get tan 30° =perpendicularbase=h100-x
We know that tan 30°  is equal to  13.
Therefore, we get
13.= h100-x
3h=100-x
Now, substituting the value of h from the equation (1) in the above equation, we get
3h =100−h
3h+h =100
⇒h=1001+3=36.6m
Hence, the height of the lighthouse is equal to 36.6m.
 
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