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Q.

Two ships are there in the sea on either side of a light house in such a way that the ships and the light house are in the same straight line. The angles of depression of two ships as observed from the top of the light house are 60 °   and 45 °  . If the height of the light house is 200 m  , find the distance between the two ships.

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a

316 m

b

416 m

c

516 m

d

616 m 

answer is A.

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Detailed Solution

Given that two ships are there in the sea on either side of a lighthouse in such a way that the ships and the lighthouse are in the same straight line. The angles of depression of two ships as observed from the top of the lighthouse are 60 °   and 45 ° .  
We have to find the distance between the two ships if the height of the lighthouse is 200m.
In a right-angle triangle tanθ=  Opposite side   Hypotenuse  .  
Let d be the distance between the two ships. Suppose the distance of one of the ships from the light house is X meters, then the distance of the other ship from the light house is (d-x) meter.
Question ImageIn right-angled ADO   , we have.
tan45 ° = OD AD = 200 x 1= 200 x x=200….(1)   In right-angled BDO  , we have
tan60 ° = OD BD = 200 d-x 3 = 200 d-x d-x= 200 3   Putting x=200. We have:
d-200= 200 3 d= 200 3 +200 d=200 3 +1 3 d=200×1.58 d=316 (approx.)    Thus, the distance between two ships is approximately 316 m.
Therefore, the correct option is 1.
 
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