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Q.

Two short bar magnets of length 1 cm each have magnetic moments 1.20 A m2 and 1.00 A m2 respectively. They are placed on a horizontal table parallel to each other with their N poles pointing towards the South. They have a common magnetic equator and are separated by a distance of 20.0 cm. The value of the resultant horizontal magnetic induction at the mid-point O of the line joining their centres is close to n×10-4 Wb/m2. Then the value of n is

(Horizontal component of earth's magnetic induction is 3.6×10-5 Wb/m2 )

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a

2.53

b

2.54

c

2.55

d

2.56

answer is D.

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Detailed Solution

The situation is as shown in the figure.

Question Image

As the point O lies on broadside position with respect to both the magnets. Therefore, The net magnetic field at point O is

Bnet =10-710×10-23[1.2+1]+3.6×10-5 =10-710-3×2.2+3.6×10-5 =2.2×10-4+0.36×10-4=2.56×10-4 Wb/m2

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