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Two short bar magnets with magnetic moments 8Am² and 27Am² are placed 35cm apart along their common axial line with their like poles facing each other. The neutral point is

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Midway between them

21 cm from weaker magnet

14 cm from weaker magnet

27 cm from weaker magnet

answer is C.

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Detailed Solution

At the neutral point , k $\frac{2 M_{1}}{x^{3}} - k \frac{2 M_{2}}{{(d - x)}^{3}} = 0$

From weaker magnet , $x = \frac{d}{{(\frac{M_{2}}{M_{1}})}^{1 / 3} + 1}$

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